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 Kathy! Is that you??? 10/Jun/17 1:48 AM |  |
 Basic techniques to UP = 33. Hopefully, this is clear enough. I'm open to suggestions if there is a cleaner or clearer way to present the idea:(4)a8 = a4 - b6 = HP(14)gh6|(14)h8 - (1)h7 = f7 - (1=7)f1 - h1 = h4 - (7=24)b46 => -4b9 ; UP = 81 10/Jun/17 5:27 AM |  |
 #28 34@ef2=>[f2<>1 & 2@de3=>i3<>2] 17@d8f7=>d8f7<>389=>9@e789=>e13<>9 #33 179@d138=>d6<>9#34 1?@d8=>h8=4=>a4=4=>g6=4=>g1….9<>1=>d8<>1VHBC to #81V:Only cell left in Vertical column for this More... 10/Jun/17 6:27 AM |  |
 Hi rwmI can't more easily present a path to show b9 <> 4 then you have.But d8 <> 1 can be easily presented, as shown above.Cheers Les. 10/Jun/17 6:47 AM |  |
 30:10 10/Jun/17 6:49 AM |  |
 lcls to 331. Almost turbot fish (4)h6=b6-b9=a8 with (4)g6 as a fin:(1=4)h8-[TF(4)h6*=b6-b9=a8]=(4-1)g6=(1)g8 =>-1d8; singles to 81The same logic is in1. Kraken row (4)bgh6 =>-1d8; singles to 81||(4)b6-b9=a8-(4=1)h8||(4-1)g6=(1)g8||(4)h6-(4=1)h8 10/Jun/17 7:18 AM |  |
 Hi rwm, the idea behind your path is clear.I would not notate your node HP(14)gh6|(14)h8 - (1)h7 as you did, because you need both the pair (14)gh6 AND the bivalue (14)h8 for the conflict with 1h7.To me, the symbol | stands for the boolean operator OR while you mean AND. My suggestion:HP(14)gh6 & (14)h8 - (1)h7 Best regards, cenoman 10/Jun/17 7:37 AM |  |
 1. Unique possibilities to 33.2. Whether a8=4,h8=1;OR a4=4,gh6=14;h7=26.UP81. 10/Jun/17 8:00 AM |  |
 I got UP to 81. 10/Jun/17 2:16 PM |  |
 2:47 :) 10/Jun/17 5:45 PM |  |
 Hi RWM, I think you need go no further than '-(1)h7' in your chain. Because you have shown that both(4)a8 which results in (1)h8, and (4)a4 which results in -(1)h7, has the same result, namely -(1)h7, which solves the puzzle. Best Regards, Alfred. 10/Jun/17 5:58 PM |  |

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