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Submitted by: Gath

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Basics to 37
1. if b3=7 => b2=8 h2=7 bh23=78 =>b2=7 solve
if h5=1 => hi59 =16 => h2=1 solve
11/Aug/18 3:23 AM
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1. Unique possibilities to 37.
2. Whether b9=5,b6=6;OR b9=8,b2=7=i3;d6=7.UP81.
11/Aug/18 4:35 AM
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#38 5?@b6=>13@cg6=>i6=7=>h2=7=>b2=8=>b9={}=>b6<>5
11/Aug/18 5:20 AM
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Beautiful, photo! Wonder where this is?
11/Aug/18 5:43 AM
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Hi serban. I think your UR logic today is not valid, because some of the cells are already givens. For example, 6 @ h9 and 6 @ h5 are givens. So 1 @ h5 would not be ruled out.UR logic only works where you can't resolve which is 1, and which is 6. The same applies to your 78 example, where h3=8 is More...
11/Aug/18 5:43 AM
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Even today's Tough has 79 @ ab25, 78 @ hi34, and 57 @ ef18.
11/Aug/18 5:55 AM
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Also 28 @ cd12,45 @ fi12,23 @ dg23 and 57 @ b123 !
11/Aug/18 6:07 AM
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I'm with Jacalmi on this - if ever a photo needed a caption, this is one!
11/Aug/18 6:45 AM
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Where is that??? Amazing. Somewhere in historic Europe/Eastern Europe I should think.
11/Aug/18 10:40 AM
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Site of a rebuilt 16th-century Ottoman bridge in the city of Mostar Croatia which was destroyed in the Bosnian Civil war.
11/Aug/18 1:46 PM
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In Bosnia not Croatia.
11/Aug/18 1:51 PM
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Thank you for that information, Les.
11/Aug/18 3:38 PM
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Just googled and saw some images of the bridge and the city. What a terrible waste of people and old historic buildings.
11/Aug/18 3:43 PM
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Hi Alfred
if h5=1 => g5=4 g5=3 OR g5=5
if g5=3 => b2=7=h2
if g5=5 => g7=0
=> h2=1 solve => i3=7 b2=7 c2=8
h4=7 UR 78 hi34
Best regards Serban
11/Aug/18 3:53 PM
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Les for the info. Terrible what happened though.
12/Aug/18 4:19 AM
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