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Submitted by: Gath

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 great pic 15/Mar/11 12:01 AM |  |
 What a nice place for the Governor General, June! 15/Mar/11 12:09 AM |  |
 SE=8.4 15/Mar/11 12:18 AM |  |
 2 aic + kraken (better probable) 15/Mar/11 1:40 AM |  |
 June - you must have been up in the air for this picture! What an estate! 15/Mar/11 1:58 AM |  |
 1 aic + kraken (now looking to avoid kraken) 15/Mar/11 2:23 AM |  |
 3 aic 15/Mar/11 2:48 AM |  |
 1.SST to UP232a. (3)c7=a9-(259')a569=(2)a23-{(124)bge2=(678)g256-(6=249)bgi9}> -2c7b3678 -4adf9 -9f92b. (6=3)e7-c7=(3-6)c1=b3 > -6e33. (8=146)df1e2-(6)c1=c4-(56=8)h24-XW:hi18=df1 > +8df1, UP81 15/Mar/11 3:00 AM |  |
 so many possible paths - probable above can be improved. 15/Mar/11 3:08 AM |  |
 I would be dissappointed if the loop: {(6=249)bgi9-(124)beg2=(678)g256} wasn't the key to unlocking this one. 15/Mar/11 3:15 AM |  |
 I lived and worked there for a couple of years in my younger days. 15/Mar/11 5:33 AM |  |
 Aide-de-camp, Ian? I think we all would give our eye teeth for a job in those surroundings!! Alas, I only can pass by on the ferry, and wish!! 15/Mar/11 9:47 AM |  |
 IMO, a great puzzle for finding many continuous loops today. Kobold, that is one very elegant solution! Although it does not effect the solution, I think the fantastic Loop you found additionally justifies eliminating (14) in row 2 outside of bg32. Perhaps also (7) in row g outside of the pattern. 15/Mar/11 1:09 PM |  |
 OOPS! I meant (14) outside of beg2. Sorry. 15/Mar/11 1:12 PM |  |
 Wonderful picture June, and wonderful memories Ian!! 15/Mar/11 1:55 PM |  |
 As far as I could get:1. Note i56=23:e28=14.Unique possibilities to 23.2. If e3=6,e7=3;both 36 cannot occupy c1.So e3=9.UP24.3. Whether e5=6;OR e7=6=g9;g5=7.UP27.4. Whether h2=5;OR h2=8,eg2=14,b2=2,bi9=49,g9=6;g4=68.UP28.Here I found 2s locked at b29;9s locked at bi9,triple 146 More... 15/Mar/11 8:44 PM |  |
 Not as difficult as I thought it would be. I worked at Admiralty House for a (very) short time lots of years ago - it really is a lovely place with a terrific view over the harbour. 15/Mar/11 8:52 PM |  |
 Steve: I thought about the extra eliminations but wasn't 100% sure. You are right. The partioned 'pivot' cell - g2 - in this type of wrap deduction confused the issue for me, because cell is AALS. The pattern behaves exactly like a normal ALS though. Thanks for heads up on that. 15/Mar/11 10:33 PM |  |
 After kobold's excellent solution,my long path:1)SSTS to UP=232)(9=6)e3-b3(6-3)c1=c7-(3=6)e7,=>e3<>6.UP=243)(6):e5=e7-h7=h4,=>df4g5<>6. UP=284)(8=142)geb2-(2=496)bhi9-(6=8)g6,=>f2<>14,adf9<>49,b3678<>25)(2479=1) More... 15/Mar/11 11:41 PM |  |

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