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 Lovely lavender, Sue! 17/Jan/13 12:35 AM |  |
 1. Note f456=189 etc.Unique possibilities to 35.2. Whether g5=6;OR g5=3=a4;d4=6.UP81. 17/Jan/13 12:49 AM |  |
 0. Standard techniques UP 371. (1=7)i8-i2=(7-56)ch2=(5)b2-b6=(5-3)d6=(3)i6 =>i6<>1 UP 81 Hi Alfred. I agree with d4=6. I then get UP 51, not 81. 17/Jan/13 1:07 AM |  |
 This is one thriving and happy Clematis, Sue! So many blossoms! 17/Jan/13 1:15 AM |  |
 #1. LS and LC; UP37#2. Solving row 6 : b6=5->contradiction; UP81 17/Jan/13 1:27 AM |  |
 Hi, Cenoman. I think you forgot c3=5! I think you should have written : (1=7)i8-7i2=7h2-[5h2=5h3-5c3 and 6h2=(6-5)c2]=5b2-5b6=(5-3)d6=3i6 :=> -1i6; UP81 Best Regards, JC. 17/Jan/13 1:35 AM |  |
 Hi, JCc3 can be omitted. Due to the bilocation 6c2=6h2, you get an AHS 56ch2 (almost hidden pair), in strong link with 5b2 on one side, and conflicting with 7h2 on the other side. ('pseudo-case' in French...)With ALSs you could write it: 1=7)i8-7i2=2589abei2-5b6=(5-3)d6=(3)i6 More... 17/Jan/13 2:17 AM |  |
 You are right cenoman. I need another step:3. Whether d5=3,i5=8;OR d5=5=c3,h3=8;i2=7.UP81. 17/Jan/13 3:03 AM |  |
 Hi Cenoman. Of course ... You're right. How could I have missed it ! :( Best Regards, JC. 17/Jan/13 4:36 AM |  |
 25 g89=59=>g3<>529 e89=35=>e8<>636 e56=47=>e5<>237 g89=59=>g5<>9 a5=2=>a4=1=>[c5=3&(d4=3=>h4=6)]=>g5={}=>a5<>252 More... 17/Jan/13 7:23 AM |  |
 Nice Clemantis, Sue. Thanks for photo 17/Jan/13 7:05 PM |  |

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