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Submitted by: Gath

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8a68 -> 1 unique solution
02/Dec/16 1:17 AM
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#28 148@e456=>df5f6<>148
#30 4@ac8=>f8<>4 36@a47=>a4<>5&a6<>3
#32 49@c18=>c8<>2 9@bc1=>fh1<>9 More...
02/Dec/16 8:47 AM
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Standard techniques up 29
1. (8)a6=a8-(8=7)f8-(7=9)f6-d4=(9-5)g4=(5)b4 =>-5a6 up 31
2. (47=8)a26-(8=1264)bceg5 =>-4g2
3. (5)g6=(5-4)g3=i3-(4=6)i4-(6=2)h5 =>-2g6
4. (2=6)h5-(6=279)g2h12-(9)d2=(917-2)d347=de9-ghi9=(2)i8 =>-2i6
5. More...
02/Dec/16 9:16 AM
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1. Note a47=36,d4f6=79.Unique possibilities to 29.
Making use of the 48 Unresolvable Rectangle @ df19:
2. Whether f8=8,a28=47;OR df9=48,a2=7 to avoid the UR;a6=58.
3. Whether d4=7,g4=9,b4=5;OR f6=7,f8=8;a6=8.UP81.
02/Dec/16 9:39 AM
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Hi Les, After 5@a6.......can't 9 still occupy f6.I think you need a few extra elliminations to reach a contradiction.
Best Regards, Alfred.
02/Dec/16 9:49 AM
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Hi Alfred,
I sure did leave out a few eliminations.
Thanks Les
02/Dec/16 2:55 PM
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#28 148@e456=>df5f6<>148
#30 4@ac8=>f8<>4 239@i689=>i4<>3 3@hi6=>a6<>3 36@a47=>a4<>5&a6<>3
#32 49@c18=>c8<>2 9@bc1=>fh1<>9
#32 More...
02/Dec/16 2:56 PM
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2)AUR(48)df19:(8)b9=(4)c 1-a2=(4)a8,=>a8<>8.UP=81
02/Dec/16 4:17 PM
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@sotir very nice UR move!
02/Dec/16 9:03 PM
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I support peterj congratulating you, sotir.
This UR step is a piece of anthology. Should enter any UR tutorial !
03/Dec/16 4:28 AM
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Thanks peterj and cenoman.When I posted solution
didn't see Alfred's path that is the same.
Congretulation Alfred.IMO you are the best using
AUR to solve tough puzzles.
Thank you all and best regards.
03/Dec/16 7:45 AM
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sotir is right, one must give to Caesar what is Caesar's and to Alfred what is Alfred's...
So, congratulations to you too, Alfred. When I reconnected on December 3, my attention was drawn on peterj's message. My laziness then made me read only Eureka paths...
Best regards, cenoman.
03/Dec/16 8:56 AM
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Alfred's path:
1)AUR(48)df19:(8)f8-a8=(8)c6; (4)ac1-(4=7)a2,=>c6<>7
03/Dec/16 9:12 AM
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Sorry, 1)=>a6<>7
03/Dec/16 9:58 AM
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30/Jan/17 7:43 AM
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