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 8a68 -> 1 unique solution 02/Dec/16 1:17 AM |  |
 #28 148@e456=>df5f6<>148#30 4@ac8=>f8<>4 36@a47=>a4<>5&a6<>35?@a6=>[e6=8&a8=8=>f8=7]=>f6={}=>a6<>5 #32 49@c18=>c8<>2 9@bc1=>fh1<>9 More... 02/Dec/16 8:47 AM |  |
 Standard techniques up 291. (8)a6=a8-(8=7)f8-(7=9)f6-d4=(9-5)g4=(5)b4 =>-5a6 up 312. (47=8)a26-(8=1264)bceg5 =>-4g23. (5)g6=(5-4)g3=i3-(4=6)i4-(6=2)h5 =>-2g6 4. (2=6)h5-(6=279)g2h12-(9)d2=(917-2)d347=de9-ghi9=(2)i8 =>-2i6 5. More... 02/Dec/16 9:16 AM |  |
 1. Note a47=36,d4f6=79.Unique possibilities to 29.Making use of the 48 Unresolvable Rectangle @ df19:2. Whether f8=8,a28=47;OR df9=48,a2=7 to avoid the UR;a6=58.3. Whether d4=7,g4=9,b4=5;OR f6=7,f8=8;a6=8.UP81. 02/Dec/16 9:39 AM |  |
 Hi Les, After 5@a6.......can't 9 still occupy f6.I think you need a few extra elliminations to reach a contradiction.Best Regards, Alfred. 02/Dec/16 9:49 AM |  |
 Hi Alfred,I sure did leave out a few eliminations.Thanks Les 02/Dec/16 2:55 PM |  |
 #28 148@e456=>df5f6<>148#30 4@ac8=>f8<>4 239@i689=>i4<>3 3@hi6=>a6<>3 36@a47=>a4<>5&a6<>35?@a6=>[e6=8&a8=8=>f8=7]=>f6={}=>a6<>5 #32 49@c18=>c8<>2 9@bc1=>fh1<>9 #32 More... 02/Dec/16 2:56 PM |  |
 SE=7.2SSTS1)(5)b4=(5-9)g4=d4-(9=7)f6-(7=8)f7-a8=(8)a6,=>a6<>52)AUR(48)df19:(8)b9=(4)c 1-a2=(4)a8,=>a8<>8.UP=81 02/Dec/16 4:17 PM |  |
 @sotir very nice UR move! 02/Dec/16 9:03 PM |  |
 I support peterj congratulating you, sotir.This UR step is a piece of anthology. Should enter any UR tutorial ! 03/Dec/16 4:28 AM |  |
 Thanks peterj and cenoman.When I posted solutiondidn't see Alfred's path that is the same.Congretulation Alfred.IMO you are the best usingAUR to solve tough puzzles.Thank you all and best regards. 03/Dec/16 7:45 AM |  |
 sotir is right, one must give to Caesar what is Caesar's and to Alfred what is Alfred's...So, congratulations to you too, Alfred. When I reconnected on December 3, my attention was drawn on peterj's message. My laziness then made me read only Eureka paths...Best regards, cenoman. 03/Dec/16 8:56 AM |  |
 Alfred's path:1)AUR(48)df19:(8)f8-a8=(8)c6; (4)ac1-(4=7)a2,=>c6<>72)(8=5)a6-b4=(5-9)g4=d4-(9=7)f6-(7=8)f8,=>a8<>8.UP=81 03/Dec/16 9:12 AM |  |
 Sorry, 1)=>a6<>7 03/Dec/16 9:58 AM |  |
 1:09:43 30/Jan/17 7:43 AM |  |

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