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Submitted by: uno hu

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lcls to 30
1. (6)f4=f9-(6=8)h9-h6=b6-(84=3)bd4 =>-3f4; singles to 81
02/Apr/17 12:51 AM
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Here is a SE 7.9 to play with.
065070040080540020001000000010002086000000000920400070000000200040069050070020610
02/Apr/17 2:30 AM
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site puzzle SE7.3
Solution same as cenoman.
02/Apr/17 2:31 AM
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12:32
02/Apr/17 2:43 AM
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It is unique and a very nice shelter too. Wilodene.
02/Apr/17 3:11 AM
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#28 146@g123=>g5<>1
#31 19@a6c5=>b4<>1
3?@f4=>f9=6=>h9=8=>g4=8=>b4=4=>d4={}=>f4<>3
VHBC to #81
V:Only cell left in Vertical column for this candidate
H:Only cell left in Horizontal row for this More...
02/Apr/17 4:03 AM
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Good roof shape for places with heavy snowfall.
02/Apr/17 4:21 AM
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'Haus Wind'
02/Apr/17 6:33 AM
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Jim's SE 7.9 - lcls to 37
Jim's SE 7.9 - lcls to 37
//Kite (5)f1=a1-b3=b5 =>-5f5
1. Kraken column (5)f134 =>-9h3; lcls to 43
||(5)f1-a1=a56-(5=3)b5-h5=(3)h3
||(5-47)fi3=(7-1)d3=(1-9)d9=e7-b7=(9)b3
||(5)f4-gi4=(54-9)g56=(9 )h5
2. (9)i1=c1-b3=b7-e7=(9-1)d9=(1-7)d3=(47)fi3 =>-9i3; singles to 81=>-9i3; singles to 81
02/Apr/17 6:41 AM
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Jim's SE 7.9:
1. Unique possibilities to 37.Note gi7=57.
Making use of the 38 Unresolvable Rectangle @ ef47:
2. Whether e7=9;OR b7=9,ef7=38,gi4=3(or else UR),h3=3=d2,d1=8=c3,b3=5,e3=1=d9;d6=9.UP81.
02/Apr/17 7:15 AM
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Here's my krakenless solution to the SE 7.9
#1 SSTS to UP37.
#2 (5)a1=b3-(5'=3)b5-h5=h3-(35'=1)e3-d3=(1-9)d9=e7-b7=b3 -> -5b3; UP41.
#3 turbot (3)h5=h3-b3=c1 -> -3c5
#4 (5)f3=f4-(5=9)e6-e7=b7-b3=h3-h5=(HP(49)-5)g56=e6 -> -5f4; UP81
02/Apr/17 10:15 AM
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Very nice path Alfred !
I can't resist writing it in Eureka:
UR(38)ef47 using externals
(3)b7==(3)gi4-(3=9)h5-h3=(9)b3 =>-9b7; singles to 81
02/Apr/17 11:41 PM
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alfred and cenoman's solution is actually a dynamic chain that combines the implication d6<>9 -> d9<>1 -> +1d3 with a second chain d6 <>9 -> +3h3:
This second chain has the UR built into it.
More...
03/Apr/17 1:54 AM
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Hi cenoman. You found a much shorter chain, but I think you only show that h3<>9:
Whether b3=9;OR b7=9,gi4=3;h3=3.UP43.
Don't you need to also reach d9=1,e7=9, to show that b7<>9 ?
Best regards, Alfred.
03/Apr/17 7:12 AM
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Hi Alfred and Jim,
I am confused with your comments. In French we would say you are 'looking for noon at 2pm' ('chercher midi à quatorze heures'). I wonder why you do not read exactly what I have written, i.e. a static chain starting at 3b7 and ending at 9b3. 3b7 OR 9b3 =>-9b7. What is wrong More...
03/Apr/17 6:30 PM
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Hi cenoman.After 9@h5 you seem to assume that 9@b3 is forced, but on my grid, 9 can also occupy i3 or c3 in row 3, or b7 in column b.

Best regards, Alfred.
04/Apr/17 12:34 AM
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cenoman, I always appreciate your comments. Best wishes, Jim.
04/Apr/17 12:55 AM
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Jim, Alfred,
I apologise. I didn't check the end of my chain, thinking that you were in disagreement with the start.
You are right, the link 9h3=9b3 is in my dreams.
I must have been out of my brain that night.

My mistake. Very sorry.
Best regards, cenoman.
04/Apr/17 6:52 AM
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No apologies needed, cenoman. But your kind words certainly are valued.
J
04/Apr/17 7:33 AM
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Hi cenoman.On April 2nd. we had daylight saving here in Sydney. Meaning that we 'found noon at 1pm'. Maybe that explains your fuzzy logic!

Best Regards, Alfred.
04/Apr/17 7:46 AM
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