Sudoku Puzzles

Hopefully this one won't be as tough as yesterday.

26:20

I've done this picture before and I STILL don't know what it is.

10:41 Oh! Who did this? I wish I had a better memory! I remember another view of this colorful scene!

It may have been Wagdy's or Appy's...

16:56 Maen! Pretty lights, looks like a festive place. Not a difficult tough today...

Somewhere in the old Soviet Union???

OOOh. It is very colorful. Wagdy, is this one of your?

I peeked on Wagdy's page. It's his! Go see his other photos! They're great!

EZ puzz ...

Thanks again, Wagdy>

I just love the color in this photo.

11.01 OO look at all the pretty colours.

A path:

1) Start at 23, bassic techniques to UP=30
(note np: g18=58, h28=17)
2) Coloring(2):g56=g7-i8=f4, -->f56<>2, UP=59
3) XW(7) atb28-h28, -->ac2,i8<>7
4)AUR(58) at gi18, -->h2<>7, UP=81

sotir,

I believe your conclusion in step 2 is invalid. One can show that 56g2==8f2, but this does not prove that 56f<>2.

Suppose that 8f<>2. Then either 5f or 6f must be 2.

Justin and sotir, I agree with justin. many of your proofs do not eliminate what is claimed unless i am wrong. please explain. chief

Hi Justin and Chiefmsb,
The explanation for second step is very simple:
Two endpoints of the chain:g56=2==f8=2 (sorry,I have
Written by mistake f4).
If g56=2,-->f56<>2
If f8=2 ,-->f56<>2
So,in both cases f56<>2.
Regards, Sotir

26 mts.

sotir, your reasoning is a mystery to me. you can'tlook at g56 as a unit. if g5 is a 2 f6 can be a 2.

Hi Justin and chiefmsb,
I want to apologize to you for my rash response.
Your explanation was very clear. Step 2 is invalid.
I'll try not to make this kind of mistakes.
Thanks for your help.
Sotir.

sotir, no problem but many of your proofs have this type of reasoning. whenever you have two numbers side by side in a box they don't 'cancel out' two numbers side by side in an adjacent box. the same goes for chains as well. chiefmsb