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 Indicate which comments you would like to be able to see GeneralJokesOtherSudoku Technique/QuestionRecipes
 UP30; [4d3=7b3-(7=958)beg3-8h6=(8-2)h2=2h3]-(2=7)d3; UP81 25/Dec/16 1:58 AM |  |
 51:44 25/Dec/16 2:55 AM |  |
 #25 359@e456=>e2<>39 28@eh2=>acd2<>28 #26 469@ef1f3=>ef1f3<>378 #28 3@d12=>d9<>3#31 6@b13=>b4<>6 2?@d3=>{e2=8,b7=2=>d7=8=>h6=8,b3=7=>b4=9=>e4=5}=>g4={}=>d3<>2VH BC to #81V:Only cell left in More... 25/Dec/16 6:28 AM |  |
 1. Note e28/h2=28.Unique possibilities to 30.2. Whether h2=8,e2=2;OR h6=8,eg4=59,b4=7;OR h7=8,d7=2;d3=7.UP81. Hi JC, could you check some typos (2d3,not 4d3) and (beg4,not beg3).Also,after -8h6, you have not yet shown that 8 @ h2, because 8 @ h7 is still possible? Maybe if you start your chain at d7, instead of d3, that would make it work?Best Regards, Alfred. 25/Dec/16 9:12 PM |  |
 Hi again JC. I just noticed that: Whether d7=8;OR e8=8=h2;h7<>8. After which your logic works. Best Regards, Alfred. 25/Dec/16 9:27 PM |  |
 11:36 25/Dec/16 10:13 PM |  |

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