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 Not Hard <10:00 26/May/17 1:12 AM |  |
 Easy tough, as noticed by Martin(SE 7.1) lcls to 61No doubt someone will find one wing solving the puzzle. I propose another pattern: BUG+3After basics, all unsolved cells have two candidates but three: g2=h2=356, h3=234.If these three cells are left with g2=56, h2=36, h3=24 the More... 26/May/17 2:59 AM |  |
 SE 7.1#1 SSTS to UP61.(4=6)h6-(6=2)g4-h5=h3 -> -4h3; UP81 26/May/17 4:11 AM |  |
 cenoman, my BUG options were(3)h3 (same as you)(356)g2 (356)h2 since gh2 must also contain (6). 26/May/17 4:13 AM |  |
 #28 38@f78=>f8<>21 #31 15@a79=>bc78<>15#62 5?@h5=>g4=2=>g2=6=>h2=3=>h9={}=>h5<>5VHBC to #81V:Only cell left in Vertical column for this candidateH:Only cell left in Horizontal row for this More... 26/May/17 6:20 AM |  |
 14:19 26/May/17 6:22 AM |  |
 10:39 26/May/17 6:54 AM |  |
 Hi cenoman. I always have trouble following the BUG logic.You say 'If these 3 cells are left with g2=56,h2=36,h3=24', that would be a BUG pattern. Why do you mention those particular ones? What about, say, g2=36,h2=56,h3=34, or some other combination? Is it logical to say that g3=3 allows g2=56,h2=56,h3=24, (which are bi-value),therefore g3=2 is the correct solution? 26/May/17 7:20 AM |  |
 Hi Alfred,As a reminder, BUG is the acronym of Bivalue Universal Grave. Let's come back one (ot two) steps back. The BUG+1 (or shortly BUG without any number) is a puzzle configuration where all unsolved cells are bivalue cells but one, that have three candidates. If you remove from that More... 26/May/17 8:38 AM |  |
 Thanks for the detailed explanation, cenoman. I can see the usefulness of this method when there is only one cell left with 3 candidates. But when there are 3 cells with 3 candidates, it is much more complicated. Certainly in this case , where the alternate solution is simply: 'Whether g4=2=h3;OR g4=6,h6=4;h3<>4.' Best Regards, Alfred. 26/May/17 2:39 PM |  |
 Hi Alfred, I had seen the simple chain eliminating 4h3. I just took the opportunity to make some ads for the BUG method, while trying to explain how to select the killers.I always imagine that some readers are happy to enhance their solving toolbox. Best regards, cenoman. 26/May/17 5:40 PM |  |
 Hi Jim,I didn't catch your comment about the BUG+3.I also started with gh2=356, and explained how to select the killers in all 3-cells (cells with three candidates). 3 is the killer in g2 and 5 is the killer in h2. we agree that 3 is the killer in h3. This keeps +6gh2; Did you mean that More... 26/May/17 6:08 PM |  |
 Thx for the different views on solving this one... 27/May/17 5:54 AM |  |

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