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Not Hard <10:00
26/May/17 1:12 AM
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Easy tough, as noticed by Martin
(SE 7.1) lcls to 61
No doubt someone will find one wing solving the puzzle. I propose another pattern: BUG+3
After basics, all unsolved cells have two candidates but three: g2=h2=356, h3=234.
If these three cells are left with g2=56, h2=36, h3=24 the More...
26/May/17 2:59 AM
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SE 7.1
#1 SSTS to UP61.
(4=6)h6-(6=2)g4-h5=h3 -> -4h3; UP81
26/May/17 4:11 AM
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cenoman, my BUG options were
(3)h3 (same as you)
(356)g2
(356)h2
since gh2 must also contain (6).
26/May/17 4:13 AM
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#28 38@f78=>f8<>21 #31 15@a79=>bc78<>15
#62 5?@h5=>g4=2=>g2=6=>h2=3=>h9={}=>h5<>5
VHBC to #81
V:Only cell left in Vertical column for this candidate
H:Only cell left in Horizontal row for this More...
26/May/17 6:20 AM
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14:19
26/May/17 6:22 AM
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10:39
26/May/17 6:54 AM
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Hi cenoman. I always have trouble following the BUG logic.
You say 'If these 3 cells are left with g2=56,h2=36,h3=24', that would be a BUG pattern. Why do you mention those particular ones? What about, say, g2=36,h2=56,h3=34, or some other combination? Is it logical to say that g3=3 allows g2=56,h2=56,h3=24, (which are bi-value),therefore g3=2 is the correct solution?
26/May/17 7:20 AM
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Hi Alfred,
As a reminder, BUG is the acronym of Bivalue Universal Grave.
Let's come back one (ot two) steps back. The BUG+1 (or shortly BUG without any number) is a puzzle configuration where all unsolved cells are bivalue cells but one, that have three candidates. If you remove from that More...
26/May/17 8:38 AM
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Thanks for the detailed explanation, cenoman. I can see the usefulness of this method when there is only one cell left with 3 candidates. But when there are 3 cells with 3 candidates, it is much more complicated. Certainly in this case , where the alternate solution is simply:
'Whether g4=2=h3;OR g4=6,h6=4;h3<>4.'

Best Regards, Alfred.
26/May/17 2:39 PM
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Hi Alfred, I had seen the simple chain eliminating 4h3. I just took the opportunity to make some ads for the BUG method, while trying to explain how to select the killers.
I always imagine that some readers are happy to enhance their solving toolbox.
Best regards, cenoman.
26/May/17 5:40 PM
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Hi Jim,
I didn't catch your comment about the BUG+3.
I also started with gh2=356, and explained how to select the killers in all 3-cells (cells with three candidates). 3 is the killer in g2 and 5 is the killer in h2. we agree that 3 is the killer in h3. This keeps +6gh2;
Did you mean that More...
26/May/17 6:08 PM
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Thx for the different views on solving this one...
27/May/17 5:54 AM
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