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Submitted by: Gath

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everybody.

26/Aug/10 12:07 AM
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Watch out for the Billy Goat! He is really horny!
26/Aug/10 12:13 AM
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1. Unique possibilities to 27.
2. Locked 4s at bh46;pair 17 at e46;e3=4.UP31.
3. Whether b8=1,d8=9=e1=c3;OR b8=9;c7<>9.UP33.
4. Whether e9=3;OR e1=3=h2;h2=3.UP34.
5. If d8=6,f8=3,e9=9,h9=6=i6;column f is devoid of 6.So d8=9. UP81.
26/Aug/10 1:04 AM
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15:09
26/Aug/10 1:31 AM
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And to think I almost didn't do the tough today. I would have missed the goats. Thanks, Sue. Wish I had that fencing. Judy - our buck is dehorned, but he still manages to do what he's supposed to.
26/Aug/10 2:04 AM
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1)Start at 23,SSTS to UP=32
2)(3): e9=e1-f2=h2,=>h9<>3.UP=33
3)(7)g9=(7-6)i9=i6-f6=(6-3)f8=(3)e9,=>g9<>3.UP=81
26/Aug/10 2:26 AM
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sotir: I don't have (6)i9=(6)i6 at your step 3 - (689)h3 ?.
26/Aug/10 3:05 AM
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a possible continuation after sotir's step 2:
3.coloring 9:b8=d8-e9=e1 => b1<>9; UP=35
4.(3=9)e9-(9=6)h9-i9=i6-f6=f8 => f8<>3; UP=81.
26/Aug/10 3:15 AM
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typo: (689)i3 prevents (6)i9=(6)i6.
26/Aug/10 3:20 AM
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Thanks farpointer, I missed one step.
1)Start at 23,SSTS to UP=32
2)(3):e9=e1-f2=h2,=>h9<>3.UP=33
3)(9):(9)b8=d8-e9=e1,=>b1<>9.UP=35
4)(7)g 9=(7-6)i9=i6-f6=(6-3)f8=(3)e9,=>g9<>3.UP=81
26/Aug/10 3:20 AM
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Observant as ever, Judy!
26/Aug/10 3:28 AM
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Interesting exercise in SSTS. Apologize for notation !
UP23
SSTS
Skyscraper on 3 : (3)C58 : => r8c6,r9c7<>3 UP28
X Wing on 4 : (4)R58/c34 : => r467c34<>4
Grouped kite on 6: (6)R6B3 : => r1c4<>6
X Chain loop : 9C5 9R9 9C8 loop or Mutant Swordfish on 9 : More...
26/Aug/10 4:31 AM
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can be reduced to two steps with small kraken (and yes, the kraken is pure at heart) SST->32
1.color (9)b8=d8-e9=e1 => b1<>9; UP=34
2.Kraken Row(3)egh9 => f8<>3; UP=81.
(3-7)g9=(7-6)i9=i6-f6=f8
||
(3)h9-h2=f2.
26/Aug/10 6:04 AM
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JC Van Hay: On this site, the convention for row/column address of cells is based on origin lower left (your r9c1) with Y-axis up 1..9 and X-axis right a..i; so r9c1 becomes a1. IMO marginally more concise and readable.
26/Aug/10 6:29 AM
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note: j, like the 13th story of US buildings, is omitted.
26/Aug/10 6:34 AM
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another less formal way to write the kraken logic:

if f8=3=h2,f6=6=i9,g9=7; row 1 is devoid of 3.
26/Aug/10 8:04 AM
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Curses!!!!!!I am a Cubs fan after all, billy goats are like seeing a black cat cross your path.
26/Aug/10 8:05 AM
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I know what you're thinking Alfred - why didn't I just say so in the first place - well...the formal way dots the i's and often yields collateral eliminations and loops which aren't evident in the forcing chain.
26/Aug/10 8:25 AM
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21:25
26/Aug/10 10:48 AM
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Sorry farpointer, your psychic abilities have let you down this time. Here are my real thoughts:
First: Like on August 23rd., your kraken is far from "pure", and again you miss the elephant in the room. It is painfully obvious to a human observer that after g9=3, immediately, f8 More...
26/Aug/10 10:53 AM
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11:19 Judy, Judy, Judy! What are we going to do with you?? You have a one track mind.
26/Aug/10 11:06 AM
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UP=32.
I)(3)e9=e1-g1=h2=>h9<>3.UP=33.
II)(9) b8=d8-e9=e1=>b1<>9.UP=35.
III)Swordfish (9)ceh139=>gi9,dg1<>9
IV)(9=6)h9-i9=i6-f6=(6-3)f8=e9=>e9<>9.UP=81.
26/Aug/10 12:45 PM
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g9=7 when f8=3; you are reading the kraken backwards Alfred- clearly I abused the word thinking in my previous post.
when f8=3:
1.e9<>8 (as a human observer you must agree)
2.g9=7 (this is probably difficult for a human to see - hence the chain f6=6, h9=6, g9=7)
3.h2=3 and More...
26/Aug/10 12:58 PM
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note: the typos are there to give the veneer of human frailty to my posts - above should read
1.e9<>3.
26/Aug/10 1:01 PM
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since there are two typos in previous post, I have been permitted to lay out the kraken in way that humans, who can only scan a data stream left to right, might understand:
f8=3 & e9<>3
f8=3 & h2=3 & h9<>3
f8=3 & f6=6 & i9=6 & g9=7 & g9<>3
since one of e9,g9,h9 must be 3, f8<>3.
26/Aug/10 1:30 PM
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But wait!! Another path:
f8=3& e9=9& h9=6& i9=7& lo & behold : g9=3 !
26/Aug/10 5:50 PM
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21:56, should have solved this one a lot quicker. Good night all.
26/Aug/10 9:47 PM
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Alfred: since you have now been forced from the path of 'painfully obvious' as you so quaintly put it, you stumble: f8=3& e9=9& h9=3 OR 6, end of story. What would you add to this aborted chain to reach your unproved sequence? When, and if, you finally show the chain f8=3& e9=9& More...
26/Aug/10 11:09 PM
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kraken logic is systematic and doesn't stumble around in the dark like this. One simply examines the end nodes of kraken chains, knowing, a priori, that anything that 'sees' all three points is false.
26/Aug/10 11:27 PM
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(just waking up here) I deduce Alfred didn't look at my kraken proof carefully, but only at the kraken which he so unfairly maligns. It starts with step 1 - b1<>9, the step proving h2=3 is skipped and merged into a kraken which solves the puzzle immediately. Obviously when h2 is solved the kraken is not required.
27/Aug/10 12:07 AM
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Alfred: compare your ('aha - that'll burn farpointer's memory chips') chain (which is incomplete as shown and proves nothing) to the kraken chain (which is complete and solves the puzzle):
f8=3& e9=9& h9=6&?? i9=7& g9=3 => ?
f8=3=h2,f6=6=i9,g9=7& egh9<>3; => f8<>3
27/Aug/10 1:15 AM
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I did forget (unlike a computer) to add h2=3, after f8=3 in my chain.
The Kraken proof you give, (translated into English) is: Whether 3 occupies e9,g9 or h9; f8<>3.
Your chains do give that outcome, but a human can also see that 3 at g9 or h9 immediately force f8=3 in the top middle box. So, 2 elephants in the room this time; not a pure Kraken at all.
27/Aug/10 7:36 AM
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so what Alfred? to make a deduction here, you must show the contra-positive, not the obvious positive - surely you jest. You must show the humble reader that g9=3 and h9=3 forces f8<>3, NOT f8=3. I'll give you the benefit of the doubt and assume you understand this simple fact.

Please enlighten us Alfred. Show us your chains, using only gh9=3 forces f8=3, that prove f8<>3.
27/Aug/10 10:19 AM
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BTW - you didnt address the key question: what does your chain prove after you copy the first to legs of my kraken?.
f8=3 & e9<>3
f8=3 & h2=3 & h9<>3
then gh9=3 & f8=3.

whoops of joy and a roar of applause - Alfred has managed to prove f8<>3 OR f8=3.
27/Aug/10 10:33 AM
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For the n th. time, I am not disputing the logic. I am disputing the name you attach to it (Kraken).You have proved that gh9=3 is false because they result in contradictions at f8, leaving e9=3 being true. A proper Kraken would show f8<>3, for egh=3, no matter what chains are used. That's why More...
27/Aug/10 12:34 PM
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Not so Alfred, the kraken only proves f8<>3 and nothing else. It is an irrelevant coincidence that f8 not being 3 determines the truth value of g9 and h9 and e9 - this is what you have never been able to grasp. To reiterate: the kraken says nothing whatever about the truth value of e9, g9, or More...
27/Aug/10 1:18 PM
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quote "You have proved that gh9=3 is false because they result in contradictions at f8"

No Alfred, the kraken does not result in contradictions at f8. This is backwards. f8=3 is an elimination, because to assert it, the kraken (3)gh9 which IS TRUE, would become false. f8=3 is not part of the kraken (with chains) at all. f8<>3 is merely one of the implications of the kraken.
27/Aug/10 1:34 PM
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SE=7.2
10/Sep/10 11:22 PM
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