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 Indicate which comments you would like to be able to see GeneralJokesOtherSudoku Technique/QuestionRecipes
 Lovely photo. 28/Dec/17 12:05 AM |  |
 SE=9.0 28/Dec/17 12:18 AM |  |
 Including the flag in the photo makes the picture. 28/Dec/17 1:28 AM |  |
 Beautiful photo, a real saver. 28/Dec/17 8:51 AM |  |
 1:38:21 28/Dec/17 1:38 PM |  |
 Long path with one DKBasics to 261. (9)f8=(9-7)e7=(7-6)h7=(6-5)a7=(5-9)a3=(9)ef3 =>-9f2; basics to 272. (5)a3=(5-6)a7=(6-7)h7=(7-9)e7=(9-3)e3=(35)ab3 =>-27a33. (1=9)i7-hi8=(9-6)f8=f9-gh9=(657)g8.h78 =>-1g8.h784. (3=4)g4-(4=7)d4-(127=6)d8.ef9-gh9=(657)h7gh8 More... 29/Dec/17 9:03 AM |  |
 Hi cenoman. Great effort. I think I found some improvements up to your step 8:A. There seems to be no need for step 2, because after d2 becomes 3 (in step 7), ab3=35.B. A simpler Step 7: Whether a1=2=e9,ghi9=1,i7=9=e3;OR a1=6=h7,e7=7,e1=12;OR a1=7,e1=12;e5=3.(C. Is there a typo in step More... 29/Dec/17 11:29 PM |  |
 Hi Alfred. I start by your point B.- Point B. You are absolutely right. Your step 7 is simpler than mine. I remember having inserted steps 3 to 6 afterwards, without re-calculating the krakens. A second improvement to this step 7 is as follows: it demonstrates 9e3==(79)e37, thus e3<>123 More... 30/Dec/17 8:46 AM |  |
 New version, with Alfred's improvements, as discussed above.Basics to 261. (9)f8=(9-7)e7=(7-6)h7=(6-5)a7=(5-9)a3=(9)ef3 =>-9f2; basics to 272. (1=9)i7-hi8=(9-6)f8=f9-gh9=(657)g8.h78 =>-1g8.h783. (3=4)g4-(4=7)d4-(127=6)d8.ef9-gh9=(657)h7gh8 =>-3g84. (6=7)g8-d8=(79)e7f8 More... 30/Dec/17 8:51 AM |  |

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