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 5 singles; HP(29)h7i9; Swordfish{2Rows357}[(9=2)i9-2i4=2a4-(2=78=9)ab2.a1]-9i1.a9; stte 05/May/17 1:06 AM |  |
 lcls to 27//SF(2)cfh357 =>-2c24.f29.h4; lcls to 291. (2=9)i9-(9=5)i1-ghi3=(5-2)f3=(2)f7 =>-2e9.h7; singles to 81 05/May/17 1:15 AM |  |
 1. Unique possibilities to 27.2. Whether ef2=2,c2=5;OR f3=2=e9,i9=9,i1=5=ef2,c2=2;a12b2=789.UP81. 05/May/17 2:55 AM |  |
 Basic techniques (excluding SF(2)) to UP 27. As a curiosity, the following chain contains overlapping subchains (one of which gives the swordfish eliminations), which are delimited by # and \$:#(9)a1 = HP(19)bc3 - \$(2)c3 = f3 - e2 = e9 - (2=9#)i9 - (9=2)h7 - h5 = (2\$)c5# subchain => -9i1 More... 05/May/17 3:08 AM |  |
 #28 9?@i1=>h7=9=>i9=2=>e2=2=>c2=5=>78@ab2=>a1={}=>i1<>9#29 3@ghi3=>d3<>3=>78@d3f1=>235@cef2=>a2<>2VHBC to #81V:Only cell left in Vertical column for this candidateH:Only cell left in Horizontal row More... 05/May/17 8:13 AM |  |
 Hi rwm,welcome on this forum!Your chain gives a nice 1-step path.Just a minor comment: you do not need the two subchains. The # subchain does the job:(9)a1 = (19-2)bc3 = f3 - e2 = e9 - (2=9)i9 =>-9i1; lcls to 81After i1=5 you have d3.f1=ab2=78 =>a1=9, a4=2; singles to 81.Best regards, cenoman. 05/May/17 6:11 PM |  |
 19:47 06/May/17 8:54 AM |  |

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