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Submitted by: Gath

 Indicate which comments you would like to be able to see GeneralJokesOtherSudoku Technique/QuestionRecipes
 To Steve and Pat Hi guys, it is a little bit strange that the complexity of a puzzle is decided based upon complexity of a proof. Though the two are related the relationship is not one-to-one. I don't know how but complexity of the puzzle must be defined by its initial grid. Could it be defined by initial number of candidates in each cell? |  |
 Hi all. |  |
 Very easy this time. I just happened to start with the key. Start at 22 filled, easy placements to 25. If f2/3=6, then f6=2, f6=5, f9=8;d4=6, so e4/5/6=1, e7=8 which is not possible. Therefore f6 must be 6. Easy placements to the end. Sorry I don't know the correct notation. |  |
 8:00I believe Steve Irwin the 'Crocodile Hunter' has been killed by a Stingray whilst filming underwater today. |  |
 This is a kind of photo I like to see. |  |
 no,i didnt find it very easy..ok not very tough either..finished in say around 15 to 20 mintes??(forgot the timer)and saw a pic that is not a usual one..hi lil turtle welcome..my how innocent it looks..wonderful pic. |  |
 Hello all, Having had the option of BBQ and shiraz last night, I returned tonight to yesterday's puzzle to expand my proof. Just needed to show that it might be long winded but it is logical. Enjoy your week. |  |
 proving,very easily, that a 3 is ot an acceptable candidate in a pair containing it,the solution unfolds straightfirward! |  |
 18:29 |  |
 I just saw the news that Steve Irwin had been killed off of the coast of Cairns. What a huge loss to Austalia and the world. He was a vibrant and vocal environmentalist and so much fun to watch. Sympathy and prayers to his family. |  |
 Nov. 23, 2007. 24/Nov/07 12:46 PM |  |
 SE=7.2 05/Sep/10 9:55 PM |  |
 12:56 31/Dec/19 5:07 PM |  |

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