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Submitted by: Gath

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SE=7.3 UP to 26
1)2-Chain Logic:(5)g1=(138)abg7=(1472)c3689 or (5)b1-c2=(5)c5 => b1<>8,c5<>1472 (or-rule) UP=81
25/Oct/14 12:41 AM
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Fuzzy! I bet it does look like snow!
25/Oct/14 1:03 AM
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UP26; [8c2=8c89-(8=125)abg7-5h9=5h2]-5c2=5c5; UP81
25/Oct/14 1:13 AM
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Typo ...
UP26; [8c2=8c89-(8=135)abg7-5h9=5h2]-5c2=5c5; UP81
25/Oct/14 1:31 AM
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Like the others:
1. Unique possibilities to 26.
2. Whether b7=8=c2;OR b7=3,ag7=15,h2=5;c5=5.UP81.
25/Oct/14 2:27 AM
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Imagine... this lovely flower is actually on a tree - an entire tree in blossom must be quite spectacular! Its name (flaxleaf paperbark) should have given me a clue, but it didn't!
25/Oct/14 10:31 AM
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Lovely shot Kate! One of my favourite melaleucas!
25/Oct/14 1:00 PM
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(27) 8?@b1=>[g1=5&b7=3=>a7=1]=>g7={}=>b1<>8
9?@e2=>[a3=9=>c3=7&b8=9=> c8=7]=>e2<>9
(29) 5?@c2=>[g1=5&b2=8=>b7=3=>a7=1]=>c2<>5
VHBC to (81)
V:Only cell left in Vertical column for this More...
25/Oct/14 3:33 PM
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Hi Les, to solve this one, it is enough to just test for 5@c2. After c2=5,c89=8,b7=3, a7=1,g7=5; and Box H2 is devoid of 5. So c5=5.UP81.

Best Regards, Alfred.
25/Oct/14 7:33 PM
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Thanks again Alfred.
Too many visitors.
Cheers Les.
26/Oct/14 7:43 AM
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(27) 8?@b1=>[g1=5&b7=3=>a7=1]=>g7={}=>b1<>8
5?@c2=>[g1=5&b2=8=>b7=3=> a7=1]=>g7={}=>c2<>5
VHBC to (81)
V:Only cell left in Vertical column for this candidate
H:Only cell left in Horizontal row for this More...
28/Oct/14 7:00 AM
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Alfred I am not sure what Box H2 means.
28/Oct/14 7:02 AM
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