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Submitted by: Gath

 Indicate which comments you would like to be able to see GeneralJokesOtherSudoku Technique/QuestionRecipes
 SE=8.3 07/Sep/10 12:19 AM |  |
 18:40 (with interruptions!) 07/Sep/10 1:01 AM |  |
 The dreary day did not detract from the local's beauty and charm! 07/Sep/10 1:03 AM |  |
 maen all! that was tough...really out of practice lately... 07/Sep/10 1:47 AM |  |
 too many steps for reasonable proof. 07/Sep/10 5:13 AM |  |
 Hi Sotir & FarpointerHere's a continuous loop move that might help.UP=2914 grouped M-Ring (b256-a135) Pivot at (14)b2 forces (14)a5 => a5<>59,b1<>4,b3<>1 07/Sep/10 5:58 AM |  |
 Bud: I found a solution, about 4..5 chains plus 2 krakens, too gnarly to merit a post. I will search for simpler path if time available.BTW: your step as AIC is one of my initial chainsloop (9=5)a4-(145=9)b256 => a4<>95,b3<>1,b1<>4. 07/Sep/10 7:17 AM |  |
 the key seems to lie in eliminating 5's in Box h5, to connect disparate loopish deadends for fruitful chaining, couldn't do much with AUR's. 07/Sep/10 7:21 AM |  |
 typo a5<>95. 07/Sep/10 7:31 AM |  |
 Too long path for this one:1)Start at 23,SSTS to UP=292)(1)a5=a3-(1=4)b2-a1=(4)a5,=>b3<>1,b1<>4,a5=143)(4)a5=(4-5)a1=(5-9)a4=(9)b5 ,=>b5<>44)FXW(5):g456=g8-d8=d5,=>hi5<>55)YW:(3)h5=h1-(3=4)d1-a1=(4)a5,=>h5& More... 07/Sep/10 8:41 AM |  |
 5)To read:YWS9) " :(5)i6-(5=8)g610) " :(hp26=2)cgf8-(2=9)f9 07/Sep/10 9:09 AM |  |
 As reference on using AURs. After UP29, look at AUR(36)hi15 => (2)i1=(6)g45h4Presenr as Kraken cell (145)b6 => hi5<>6(4)b6-(4)i6=(34)hi5 ||(1)b6-a5=a3-(1=3)d3-(3=2)i3-(2)i1=(6)g45h4 ||(5)b6-b1=(5-4)a1=(4-1)a5=(1)a3-(1=3)d3-(3=2)i3-(2)i1=(6)g45h4 07/Sep/10 5:02 PM |  |
 11:23 07/Sep/10 8:43 PM |  |

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