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# Tough Sudoku for 22/April/2013

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Submitted by: Gath

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 Looks like a festive gathering to me! 22/Apr/13 12:19 AM 1. Note h57=26.Unique possibilities to 29.2. If h5=6,b5=89,a9=8; there are no candidates for c1; because c1 cannot be 89(to avoid the 89 Unresolvable Rectangle at bc15); but then c1=47, creating a 47 UR at ac17. So h5=2. UP81. 22/Apr/13 1:05 AM SER=7.2 UP=271)(6)h7=(47)ac7 or (6)h5-b5=(6)b78 =>ac7<>6 UP=282)(8=6)a8-b9=(8-4)e9=(4)h9=(2)i8=(6)h7 => g8,b7<>6 UP=293)(-5)g7=(5=3)b7=(3-6)b8=(6)b5-h5=(6)h7 => g7<>6 UP=81 22/Apr/13 1:48 AM 1: UP27 2: (6=89)b15-(8)b89=(8-4)a8=(4-2)f8=f7-(2=6)h7 => h5<>6, UP81 22/Apr/13 2:04 AM Hmm. Rechecking my proffered solution leaves a doubt that I had left out 4 as a possibility in i8. Anyway, with that possibility still there 4 is not strong in af8, so my chain is probably invalid. Sorry. 22/Apr/13 2:14 AM Like Jyrki's ... ! #1. 3 Singles; UP25HP(26)h57; UP27HP(12)a46 LC(1,3,5); [FXWing(6b578.h57) :=> -6ac7;] LC(7)NP(47)ac7; NP(12)ai4; LC(2); HP(24)fi8; UP28; LC(9) #2. Chain[6] : 2i8=(2-6)h7=6h5-(6=89)b15-8b9=(8-4)e9=4f8 :=> -4i8, -2f8; UP81 22/Apr/13 3:35 AM Read FXW... instead of [FXW...] 22/Apr/13 3:59 AM Sure does Vici!Hello everyone! 22/Apr/13 8:36 AM 26 26@h57=>h5<>4828 5@c46=>c7<>5 5@h12=>h7<>5 g8=6=>h5=6=>b7=6=>{g7=5=>i8=9&b9=5=>[b8=3&e9=8]}=>d8={}=>g8<>62 9 More... 22/Apr/13 8:43 AM 2 9 More...should have appeared as29 More... 22/Apr/13 8:44 AM My step 1 should read UP27.Step 2 also works in reverse order:2. Whether b89=8,b1=9,b5=6;OR a8=8,b789=356,c1=89(to avoid 47UR),c5=6(to avoid 89UR);h5=2.UP81. 22/Apr/13 9:19 AM