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Tough Sudoku for 6/November/2018

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Submitted by: Gath

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 06/Nov/18 12:42 AM 25:21. Hi Wow_Axel. 06/Nov/18 12:54 AM Basics to UP = 271.[SS(6): i4=i1-a1=a6] = (6-9)a9 = (9-2)a2 = bc3 - (2=8)f3 - ef1 = HP(18-6)hi1 = (6)g3 => -6g6 ; UP = 81 06/Nov/18 1:31 AM 1. Unique possibilities to 27.2. Whether ac1=6=i4;OR ac1=34=eg2;i2=9.UP45.3. Whether c4=4;OR c4=2=f5,f8=1=b7,b4=4;d4=5.UP81. 06/Nov/18 1:32 AM As shown by rwm, there is no need for my step 3. 06/Nov/18 1:36 AM Basics to 271. (2)a2=ef2-(2=8)f3-gh3=(18-6)hi1=(6-9)i4=h4-h3=(9)c3 =>-9a2; singles to 81 06/Nov/18 2:25 AM Hope he was set free after the photo. 06/Nov/18 5:24 AM #28 9?@a2=>34@gi2=>h2=7=>25@ef2=>f3=8=>g3=6=>i4=6=>i1….9<>9=>a2<>9 NB/#28 679@abe9=>1@ghi9 06/Nov/18 6:29 AM Basics to 27 1.X-chain x=6 => a1<>6 if i1=6 => g6=6 a9=6 c7=9 bc3=26 f3=0 => c1=6 solve 06/Nov/18 10:06 PM