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Tough Sudoku for 16/May/2009

                 
                 
                 
                 
                 
                 
                 
                 
                 

Choose a number, and place it in the grid above.

  1 2 3 4 5 6 7 8 9
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Submitted by: basscom4life
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Steve  From Ohio    Supporting Member
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Once upon a time, a long, long time ago, I occasionally wrote a blog at this site. I have restarted the blog today.
One can find an illustrated solution to today's puzzle in that blog. A link to that blog exists in the upper right hand corner of the right hand column, under "check out the sudoku blog". It is titled "Solution path for Tough Sudoku of 05/16/09".
Today's puzzle is not really one for beginners, though, imo.
15/May/09 5:08 PM
   Shiela  From MI
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Looks like there are sun worshipers around the world!
Nice photo, Kate!
16/May/09 12:09 AM
Judy  From San Diego    Supporting Member
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Hi, Steve! back! We Old Timers from "long, long ago" have missed you!
16/May/09 12:38 AM
Dimitris  From Greece
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Nice photo Kate. Have a nice week-end all of us!!
16/May/09 1:36 AM
   Debby  From Michigan,USA    Supporting Member
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Our sun is hiding under clouds today. I am afraid more rain is on the way.

Thank you, Steve!
16/May/09 1:57 AM
   Plum  From SW Michigan, USA
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16:57 one possibility
16/May/09 3:24 AM
   Plum  From SW Michigan, USA
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My one possibility was in d3, so that jives with Steve's proof. Thanks, Steve, for the logic and illustrated steps to the solution.
16/May/09 4:19 AM
Nick  From Toronto
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Almost an hour and one half to solve.
16/May/09 4:32 AM
   johnvan  From Toronto
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very tough - too long to bother timing
16/May/09 6:49 AM
Alfred  From Sydney    Supporting Member
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Hi Steve.Here is another way of showing d3<>3,using a "super" AUR:
If d3=3,e2=5,e3=9,e1=1,e8=6.Now g56=67,g1=3,f4=6,a56=36 and f56=37.This "super" unique rectangle at afg56 cannot be resolved.
16/May/09 10:26 AM
Alfred  From Sydney    Supporting Member
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Hi again Steve.When I checked your solution more thoroughly,I found my method was equivalent to yours,just using different terminology.Sorry about the mix up.Regards, Alfred.
16/May/09 7:30 PM
Neil  From UK-Hertfordshire
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Hi Steve

Welcome back.

You chose a good puzzle to re-start your blog - I didn't have a clue on how to do it by logic, but one good guess solved it - and very many not-so-good ones didn't.

Yours bigginerly (if there is such a word)

Neil
~
16/May/09 8:33 PM
Steve  From Ohio    Supporting Member
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Hi Alfred!
I have noted that you publish quite a few solutions here. Thank-you for doing so!
Occasionally, what appears to be different will be exactly the same, or very similar. No need to apologize, albeit it is very nice, especially for other readers, to note the overlap between our approaches. Thank-you!
16/May/09 10:02 PM
Steve  From Ohio    Supporting Member
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Thanks to everyone for the kind words. They are appreciated!
16/May/09 10:03 PM
sotir  From New York
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For this one,I just found these eliminations;

e1=9,f7=3,f2=2,g56=3,hi2=5,c9=7,b2=2,b4=3,f4=1
16/May/09 11:30 PM
sotir  From New York
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SE=9.0
09/Sep/10 10:36 PM
farpointer  From Wisconsin
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3 krakens and 5 AICs w/o uniqueness
12/Jan/11 11:24 AM
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