Timer
00:00:00
Start Pause Reset
15 Comments • Previous / Next • Help

Tough Sudoku for 16/August/2009

                 
                 
                 
                 
                 
                 
                 
                 
                 

Choose a number, and place it in the grid above.

  1 2 3 4 5 6 7 8 9
Report an issue
Check out the latest post in the Sudoku Forum

Watch Amazing Blindfold Sudoku Solving Video

Submitted by: basscom4life
Indicate which comments you would like to be able to see
Steve  From Ohio    Supporting Member
Check out my page
I elected to blog this one.... Hopefully, the technique highlit is at least as clear as mud.

Cheers!
Steve
15/Aug/09 7:16 PM
Judy  From San Diego    Supporting Member
Check out my page
"Flutterby, flutterby ... fly away home!" I love the way the color of the leaves shows through the wings!
16/Aug/09 12:21 AM
   Debby  From Michigan,USA    Supporting Member
Check out my page
Beautiful butterfly, Sue!
16/Aug/09 12:41 AM
   Vibrant Vici  From California    Supporting Member
Check out my page
WOW!
16/Aug/09 1:54 AM
Jyrki  From Finland    Supporting Member
Check out my page
maEn! 12:55 Worked on e1 at the only critical step. That did it!
16/Aug/09 2:51 AM
   Shiela  From MI
Check out my page
Good eye, Judy! (I just sat there and was amazed by how the sap green color of the butterfly matched the leaf! Shows you how observant I was!)
16/Aug/09 3:54 AM
   johnvan  From Toronto
Check out my page
11:10
16/Aug/09 4:27 AM
Judy  From San Diego    Supporting Member
Check out my page
Although not necessarily faster, I found this puzzle easier and less complicated than the Hard one.
16/Aug/09 4:50 AM
Alfred  From Sydney    Supporting Member
Check out my page
1. Note pair 49 at a45 and later 78 at i45.Unique possibilities to 39.
2. If e1=6,h3=6 (to avoid the 38 unresolvable rectangle at ch13),pair 14 at ef3, and 156 have no place in row 2.Hence e1=7.UPs to 81.
16/Aug/09 10:46 AM
   fii  From NT
Check out my page
At 39 filled, FC shows that f8 cannot = 9... therefore i8 = 9 and puzzle unfolds.
16/Aug/09 3:14 PM
Dimitris  From Greece
Check out my page
Very good picture Sue
16/Aug/09 5:24 PM
Steve  From Ohio    Supporting Member
Check out my page
Alfred, very nice use of AUR 38 in your solution. One could make a, imo, simpler chain:
(AUR38)ch13 => (1)c3 = (6)h13 - (6=3)h2 - (3=1)d2 => ef3<>1 UP 81
16/Aug/09 9:51 PM
Steve  From Ohio    Supporting Member
Check out my page
Alfred, I have erred. Sorry, apparently I forgot about the possibility of (6) still at d2. Ignore my suggestion. I should have written:

(AUR38)ch13 => (3)h2 = (1) c3 - (1)a2 = (1)d2 => d2<>3 UP 81
16/Aug/09 10:04 PM
Nick  From Toronto
Check out my page
14:13
22/Aug/09 10:02 PM
sotir  From New York
Check out my page

SE=4.6
09/Sep/10 11:18 PM
Please Log in to post a comment.

Not a member? Joining is quick and free. As a member you get heaps of benefits.

Join Now Login