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Tough Sudoku for 18/March/2020

                 
                 
                 
                 
                 
                 
                 
                 
                 

Choose a number, and place it in the grid above.

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Submitted by: Gath

Indicate which comments you would like to be able to see

I am tempted to try Google Image for this odd structure!
18/Mar/20 3:42 AM
Basics to 27
1. (5)e7=(5-3)h7=d7-(3=7)f9 =>-7e7
2. (5)e7=(5-3)h7=h9-(3=794)dfi9-a9=(4)a7 =>-4e7; basics to 39
3. (6=82)a16-c4=(2-6)h4=h2-g1=(6)a1 =>-6a9; basics to 44
4. (1)e2=e1-(1=694)g134-g8=(4)e8 =>-4e2; basics to 49
5. (2=7)a9-i9=i6-(7=2)f6 =>-2a6
6. (7)c2=a2-a9=i9-(7=8)i6-a6=(8)a1 =>-8c2; singles to 81
18/Mar/20 3:43 AM
SE=7.3
Basics to UP=27
1)(3=36)d1f13-(5)f1=f8-e7=(5-3)h7=(3)d7,=>f1<>8,f3<>78,h7<>9,d9<>3
2)(5)e7=(5-3)h7=(3-1)h9=(1-6)c9=(6-4)a9=(4)a7,=>e7<>4
3)(68=2)a16-c4=(2-6)h4=h2-g1=(6)a1 More...
18/Mar/20 8:43 AM
Basics to 27
1. (4*)a7 = (46-1)ac9 = (1-@3)h9 = (3-5)h7 = (5*)e7 - (5=2783@)f5689 =>
-4*e7 and @ loop eliminations: -3d9, -9h7, -7f3, -8f13 ; UP = 39
2. (7=4691)g8431 - (1=8)e1 - e8 = (8)f8 => -7f8 ; UP = 43
3. (3)g6 = (3-1*)c6 = (1-6*)b6 = b2 - (6^)a1 = (6#)g1 - (6=987')g4.i46 - More...
18/Mar/20 12:36 PM
49:01
10/May/20 8:25 AM
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