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Tough Sudoku for 26/May/2015


Choose a number, and place it in the grid above.

  1 2 3 4 5 6 7 8 9
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Sudoku Solving Techniques

Submitted by: sudoku lover

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SE is challenged here (SE=8.3, 1.0 points)

# -(649)gi4
26/May/15 12:59 AM
Morning all
Have a good day
26/May/15 1:13 AM
One chain and two prolongations...
Standard techniques UP 23
1. (6=8)c4-c8=e8-e2=(8-1)i2=g2-1g5=(178)gi4.h5 =>-6i4
// (9=6)a4-[6c4==(178)gi4.h5]*-(4)gi4=(4)d4 =>-9g4, -9d4
26/May/15 1:18 AM
1. Unique possibilities to 23.
2. Whether a4=9=g6,d4=4;OR a4=6,c4=8=e7=i2,g2=1=i4,b4=9;gi6=94.UP26.
3. Whether g5=1=i2,e2=8;OR g5=5,h6=6=b9;c8=8.UP81.
26/May/15 2:08 AM
Lovely green photo,Bev. Parsley makes a fun puzzle too!
26/May/15 2:45 AM
#24 1?@i2=>e2=8=>c8=8=>c4=6=>a4=9=>{d4=4&g6=9=>i6=4=>[i7=6=>g9=3&i8=7=>h9=2]} =>d9={}=>i2<>1
#25 7?@i4=>h5=1=>h3=8=>i2=3=>i3={}=>i4<>7
#26 18@h5i4=>i4<>4&h5i4<>6 #27 More...
26/May/15 8:14 AM
Now that you have all that parsley, what do you do with it? Other than take great photos!?
26/May/15 11:42 AM
Hi Les. After you show that i2<>1,g2=1, then h5 and i4 become 18, and there is no need to show that i4<>7.

Best Regards, Alfred.
26/May/15 3:31 PM
A shorter step 2, after which step 3 still works:

2. Whether d5=9;OR d5=3,ac6=23,g6=9;g5=15.
26/May/15 7:24 PM
Thanks Alfred. I will check it out later.
Cheers Les
27/May/15 6:56 AM
#24 1?@i2=>e2=8=>c8=8=>c4=6=>a4=9=>{d4=4&g6=9=>i6=4=>[i7=6=>g9=3&i8=7=>h9=2]}
#25 18@h5i4=>i4<>74&h5i4<>6 #27 6@hi6=>f6<>6
VHBC to #81
V:Only cell left in Vertical column for this More...
28/May/15 10:29 AM
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