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Tough Sudoku for 3/November/2017

                 
                 
                 
                 
                 
                 
                 
                 
                 

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Sudoku Solving Techniques

Submitted by: sudoku lover

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Basics to UP = 28
1. (7)g1 = g7 - (7=3)h9 - g8 = (3-9)g2 = HP(91)ih2 - (1=6)h4 - (6=8)g6 => -8g1 ; UP = 32
2. (7): e9 = e1 - g1 = g7 => -7f7|hi9 ; UP = 81
03/Nov/17 1:07 AM
Sorry - I omitted a step. Correction to follow.
03/Nov/17 1:20 AM
Corrected solution: Basics to UP = 26
1. (9): a9 = i9 - i3 = b3 => -9a2|b8 ; UP = 28
2. (7)g1 = g7 - (7=3)h9 - g8 = (3-9)g2 = HP(91)ih2 - (1=6)h4 - (6=8)g6 => -8g1 ; UP = 32
3. (7): e9 = e1 - g1 = g7 => -7f7|hi9 ; UP = 81
03/Nov/17 1:28 AM
Basics to 26
//SS (9)a9=i9-i3=b3 =>-9b8,a2; basics to 28
1. (6=1)h4-h2=(1-9)i2=g2-(9=3)g8-(3=7)h9-g7=(7-8)g1=(8)g6 =>-6g6; basics to 39
2. UR(48)ad12 using internals
||(3)d2-d3=h3-(3=7)h9
||(7)a2-f2=(7)f79
=>-7e9; singles to 81
03/Nov/17 2:06 AM
Hi rwm,
After the skyscraper on the 9's (your new step 1.) the elimination of 8g1 should result in 'UP 39'
You get 'UP 32' with 4 singles, then NT(267) in box 9, and then 'UP 39' with 7 singles.
At 'UP 32' your final SS on the 7's is not there (7e2 still present). Typo on the 'UP' ?
Regards, cenoman.
03/Nov/17 2:16 AM
Love Columbine. I have some in my garden.
03/Nov/17 5:21 AM
#27 147@abc6=>g6<>7
6?@g6=>g4=5=>g7=7=>h9=3=>g8=9=>b3=9=>i2=9=>h2 =1=>h4={}=>g6<>6
#31 9?@a2=>i39=9=>a2<>9
#33 267@gi1i3=>h23<>2
#40 More...
03/Nov/17 7:30 AM
This is my favorite variety of columbine.
03/Nov/17 8:55 AM
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