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Brenda from Queens, New York
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Eve
From
So. Oregon
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to
you to Sudokuland, along with a Strawberry Cream Cheese Pie for you and your guests.
There’s lots to do around here, places to visit and chat. I'm just around the corner; stop in anytime for more pie and a video.
29/Nov/08 12:01 PM
mymare
From
Naperville, IL
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Hope you had a nice Thanksgiving --- I worked today so didn't join the masses in shopping. I'm near Chicago - getting a little colder each day -- take warm, Mary
29/Nov/08 1:20 PM
Grass-hopper
From
Qld
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Brenda
Make yourself at home! Feel free to kick off your shoes, get comfy & enjoy the world of Sudoku! Our International subset of the world is an interesting & sometimes eye-opening experience. Enjoy!
29/Nov/08 2:07 PM
Sophia
From
Country Vic, Aust.
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Great to have you here, so come and take a load off and enjoy, stop by some time and we can visit, cheers.
29/Nov/08 6:46 PM
Vibrant Vici
From
California
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Welcome Brenda!
Hope you enjoy your time here in Sudokuland!
We're happy to have you aboard!
Blessings!
30/Nov/08 3:14 AM
Wagdy Kamel
From
Cairo Egypt
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Dear Brenda.
You are,
.
30/Nov/08 6:41 AM
Kathy
From
Maryland/USA
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to your own page, Brenda!
Nice to meet you!
You've found a great site with lots of fun people. Visiting different pages is like taking a trip around the world. Stop by my place by clicking on the blue 'check out my page' next to my avatar. I love having guests and the door's always open
30/Nov/08 8:05 AM
Alfred
From
Sydney
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Hi Brenda.I left a comment on the March 17th page.I have trouble following ttt too.Maybe because of his layout and his use of the row/column notation.I can't use the Eureka notation, but can usually follow someone else's solution.Bit like being able to understand a language, but not being able to speak it.Most important is "=" means "enables" and "-" means "forbids".Regards, Alfred.
21/Mar/09 6:47 PM
Alfred
From
Sydney
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Hi Brenda. I checked out your 17th. April solution.Phew! Some of the sequences are very long but I think your proof is valid.A couple of points:In step 4 ,when b7=4, i2=4 too;After c7=8 in step 7,the top left box is already devoid of 1,and you need go no further.
Doing my tax return, or going through your proof;hard to decide which was more daunting !
26/Apr/09 2:58 PM
Alfred
From
Sydney
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Hi Brenda.You've been burning the midnight oil again!Thanks for translating ttt's proof so thoroughly.I'll study it,probably tomorrow,when I should have more time.Regards,Alfred.
13/May/09 1:40 PM
Alfred
From
Sydney
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Hi Brenda.Regarding the Aug.31st. Tough:
In your chain starting with c1=9,your third last term is "c8=2".On my grid,it could still be "c8=27" (part of pair 27 at c78).If this is the case,you may have to delve further to reach a contradiction.
Your 28th. April solution checked out OK.Steve,from Ohio will be rolling over in his...sleep?...,when he sees the lengths of our chains!Regards,Alfred.
01/Sep/09 5:57 PM
Alfred
From
Sydney
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Hi again.Regarding the length of chains.I think 3 steps, each 4 deep is about equivalent to one chain of depth 12, but Steve may not aggree with that.It's probably a subjective thing.The least amount of logic needed to solve a puzzle ,the better. BTW,got stuck on today's (Sept. 2nd.) tough at UP 40. Regards,Alfred.
02/Sep/09 4:33 PM
Alfred
From
Sydney
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Thanks for continuing the proof for the 26th Sept. tough.I followed your step 2 to reach b5=5,but could then only get b3=8,b6=2 (UP39).Do you need an extra step to reach your UP46, or did I miss something here?
Regards,Alfred.
30/Sep/09 10:51 AM
Alfred
From
Sydney
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Starting from the beginning again: I aggree your step 2 gives b5=5,b6=2,b3=8.UP39.But when I asked how you got further,you gave i5=2,to which I replied that i5 could still be 6 on my grid as well.(It was not 7, because 7 was locked at af5).I am still not sure how you get past UP39.
Regards, Alfred.
01/Oct/09 1:23 PM
Alfred
From
Sydney
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Thanks for the 16th Nov. solution.I made some comments on the page. See what you think.
Regards, Alfred.
24/Nov/09 1:50 PM
Gail
From
Cockatoo Vic AU
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Wishing you and your family a very Merry Christmas
and a
24/Dec/09 7:32 PM
Alfred
From
Sydney
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Hi Brenda.Your solution seems to check out OK until right near the end,when you give e6=9 in step3. This must be a typo,as d6=9 is already a given.
I couldn't work out what you meant,because I could not yet find a contradiction in column e.Here is my column e,at this stage,starting from e1: 9,2,8,(15),6,7,(15),4,3.
I have been prone to mistakes lately,so please correct me if I am wrong.Regards,Alfred.
28/Dec/09 11:40 AM
Alfred
From
Sydney
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Hi Brenda.I see it now,thanks (after e6=2).I didn't see UP26 either until Neil and Jyrki pointed it out:h8=19,h9=59 (part of the 159 triple at h389),g7=35,i7=13.This creates a Quad:1359 at gi7/h89.So 3 is locked at gi7,making e9=3 (UP26).
All the best for the New Year,Regards,Alfred.
30/Dec/09 9:58 AM
Alfred
From
Sydney
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There is a good example of an AUR in my solution for Dec. 29th.If 8 occupies c2 or c3,this would create an 89 rectangle at b56/d56.The only other place for 8 in bottom left box is b3.The 89 rectangle is called "unique".("A"stands for Almost).I think a better description is "unresolvable",because it allows two solutions.To avoid having two solutions,b3 must =8.
Best wishes,Alfred.
31/Dec/09 8:41 AM
Alfred
From
Sydney
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Hi Brenda.I followed your solution to f3=6 (steps 1 and 2),but only reached UP26.Did you maybe include a2=2 (to avoid the 28AUR) as well?
Anyway,in step 3(a),after e3=5=i2,I make i3=34 still.Can you clear that up?
Regards,Alfred.
15/Jan/10 5:52 PM
Alfred
From
Sydney
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Regarding March 18th Tough:
Hi Brenda.I can't see how you arrived at i4=8 in step 3 and also in step 4a.
In step 3,I make i5=78,i4=78,i3=2,i2=5.
In step 4a,like Neil,I make i5=8,i4=5,i3=2,i2=7.
I am not clear of the query you have about which chains to follow.Maybe you could give an explicit example.
Sorry,some of ttt's notation is beyond me.Not being used to the row/column notation doesn't help either.
Regards, Alfred.
01/Apr/10 11:48 PM
Alfred
From
Sydney
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Hi Brenda.I explained myself more clearly on the 18th April tough.Will try to make it clearer in future.
Regards, Alfred.
21/Apr/10 7:48 AM
Stephen
From
Milton Keynes, UK
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Hi Brenda. If you like words (as I do) check out "A Dictionary of Challenging Words" by Norman W Schur (Penquin Reference) ISBN 0-14-051222-5 and settle your LOGOMACHIES. You'll find it GOLUPTIOUS.
01/Jun/11 3:58 PM
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