Brenda from Queens, New York

to you to Sudokuland, along with a Strawberry Cream Cheese Pie for you and your guests.

There’s lots to do around here, places to visit and chat. I'm just around the corner; stop in anytime for more pie and a video.

Hope you had a nice Thanksgiving --- I worked today so didn't join the masses in shopping. I'm near Chicago - getting a little colder each day -- take warm, Mary

Brenda
Make yourself at home! Feel free to kick off your shoes, get comfy & enjoy the world of Sudoku! Our International subset of the world is an interesting & sometimes eye-opening experience. Enjoy!

Great to have you here, so come and take a load off and enjoy, stop by some time and we can visit, cheers.

Welcome Brenda!
Hope you enjoy your time here in Sudokuland!
We're happy to have you aboard!
Blessings!

Dear Brenda.
You are,

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to your own page, Brenda!
Nice to meet you!
You've found a great site with lots of fun people. Visiting different pages is like taking a trip around the world. Stop by my place by clicking on the blue 'check out my page' next to my avatar. I love having guests and the door's always open

Hi Brenda.I left a comment on the March 17th page.I have trouble following ttt too.Maybe because of his layout and his use of the row/column notation.I can't use the Eureka notation, but can usually follow someone else's solution.Bit like being able to understand a language, but not being able to speak it.Most important is "=" means "enables" and "-" means "forbids".Regards, Alfred.

Hi Brenda. I checked out your 17th. April solution.Phew! Some of the sequences are very long but I think your proof is valid.A couple of points:In step 4 ,when b7=4, i2=4 too;After c7=8 in step 7,the top left box is already devoid of 1,and you need go no further.
Doing my tax return, or going through your proof;hard to decide which was more daunting !

Hi Brenda.You've been burning the midnight oil again!Thanks for translating ttt's proof so thoroughly.I'll study it,probably tomorrow,when I should have more time.Regards,Alfred.

Hi Brenda.Regarding the Aug.31st. Tough:
In your chain starting with c1=9,your third last term is "c8=2".On my grid,it could still be "c8=27" (part of pair 27 at c78).If this is the case,you may have to delve further to reach a contradiction.
Your 28th. April solution checked out OK.Steve,from Ohio will be rolling over in his...sleep?...,when he sees the lengths of our chains!Regards,Alfred.

Hi again.Regarding the length of chains.I think 3 steps, each 4 deep is about equivalent to one chain of depth 12, but Steve may not aggree with that.It's probably a subjective thing.The least amount of logic needed to solve a puzzle ,the better. BTW,got stuck on today's (Sept. 2nd.) tough at UP 40. Regards,Alfred.

Thanks for continuing the proof for the 26th Sept. tough.I followed your step 2 to reach b5=5,but could then only get b3=8,b6=2 (UP39).Do you need an extra step to reach your UP46, or did I miss something here?
Regards,Alfred.

Starting from the beginning again: I aggree your step 2 gives b5=5,b6=2,b3=8.UP39.But when I asked how you got further,you gave i5=2,to which I replied that i5 could still be 6 on my grid as well.(It was not 7, because 7 was locked at af5).I am still not sure how you get past UP39.
Regards, Alfred.

Thanks for the 16th Nov. solution.I made some comments on the page. See what you think.
Regards, Alfred.

Wishing you and your family a very Merry Christmas



and a

Hi Brenda.Your solution seems to check out OK until right near the end,when you give e6=9 in step3. This must be a typo,as d6=9 is already a given.
I couldn't work out what you meant,because I could not yet find a contradiction in column e.Here is my column e,at this stage,starting from e1: 9,2,8,(15),6,7,(15),4,3.
I have been prone to mistakes lately,so please correct me if I am wrong.Regards,Alfred.

Hi Brenda.I see it now,thanks (after e6=2).I didn't see UP26 either until Neil and Jyrki pointed it out:h8=19,h9=59 (part of the 159 triple at h389),g7=35,i7=13.This creates a Quad:1359 at gi7/h89.So 3 is locked at gi7,making e9=3 (UP26).
All the best for the New Year,Regards,Alfred.

There is a good example of an AUR in my solution for Dec. 29th.If 8 occupies c2 or c3,this would create an 89 rectangle at b56/d56.The only other place for 8 in bottom left box is b3.The 89 rectangle is called "unique".("A"stands for Almost).I think a better description is "unresolvable",because it allows two solutions.To avoid having two solutions,b3 must =8.
Best wishes,Alfred.

Hi Brenda.I followed your solution to f3=6 (steps 1 and 2),but only reached UP26.Did you maybe include a2=2 (to avoid the 28AUR) as well?
Anyway,in step 3(a),after e3=5=i2,I make i3=34 still.Can you clear that up?

Regards,Alfred.

Regarding March 18th Tough:
Hi Brenda.I can't see how you arrived at i4=8 in step 3 and also in step 4a.
In step 3,I make i5=78,i4=78,i3=2,i2=5.
In step 4a,like Neil,I make i5=8,i4=5,i3=2,i2=7.
I am not clear of the query you have about which chains to follow.Maybe you could give an explicit example.
Sorry,some of ttt's notation is beyond me.Not being used to the row/column notation doesn't help either.
Regards, Alfred.

Hi Brenda.I explained myself more clearly on the 18th April tough.Will try to make it clearer in future.
Regards, Alfred.

Hi Brenda. If you like words (as I do) check out "A Dictionary of Challenging Words" by Norman W Schur (Penquin Reference) ISBN 0-14-051222-5 and settle your LOGOMACHIES. You'll find it GOLUPTIOUS.