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Tough Sudoku for 19/October/2015

                 
                 
                 
                 
                 
                 
                 
                 
                 

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Sudoku Solving Techniques

Submitted by: sudoku lover

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Posted a path to A-8,SE=8.5 (Oct 17.2015)
19/Oct/15 12:28 AM
In a lovely area.
19/Oct/15 4:50 AM
A8: the ending here is a series of patterns, aside from that very similar to sotir

// als SW:(5,64)e59/(5)ea7,(6)ac5,a6; -5a6

1. SS(4)dgh6.i59* =* [(2=8)d3-e1=(8-4)i1=*i2-(4=2)b2] - (26)d2,(63)d4,(34)d6 # -4d9

2. SF(2)bhi.249=d2 - (6)d24.h48 # -2h8
and - (6)d24.(3)dh4 - More...
19/Oct/15 5:53 AM
a busy se=8.4 (only 1 one-off kraken) [.5 + .5 + 1.0 + .5 + .25 + .75 + .25] = 3.5 **

1. (2=7)a7-c9=(7-9)e9=b9-a8=a4 # -2a4

2. (3)c56=(3-1)c2=c6-(1=9)a4-(9=5)h4-(5=3)g4 # -3b4

3. [(2)e4=b4-(2=*6)b1-(6=9)b9-a8=a4-(9=5)h4-(5=3)g4] =* (3)b1.f15 # -3e4

4. More...
19/Oct/15 6:53 AM
Hi Alfred,
I have posted again my answer to your question on page dated October 17. I don't understand what happened...
Best regards, cenoman.
19/Oct/15 7:11 AM
an improvement on the above path (same score) is:

1. (2=7)a7-c9=(7-9)e9=b9-a8=a4 # -2a4;
ext. (9)e9=(9-8)e8=c8 # -(27)c8
2. (3)c56=(3-1)c2=c6-(1=9)a4-(9=5)h4-(5=3)g4 # -3b4
3. [(2)e4=b4-(2=*6)b1-(6=9)b9-a8=a4-(9=5)h4-(5=3)g4] =* (3)b1.f15 # -3e4
4. (5=6)i9-(6=9)b9-a8=a4-(9=5)h4 More...
19/Oct/15 7:13 AM
Thanks cenoman, but I still can't see it. (See post on OCT 17th.)

Regards, Alfred.
19/Oct/15 7:54 AM
(I saw your post, but still have a problem.)
19/Oct/15 8:00 AM
A9 quite tough: Symmetry=AntiDiagonal, Start=25, SSTS=30, SG=20.25, SE=9.0
070800100120050000000000079200008004080009010000240006600000040002090300001302000
19/Oct/15 8:12 AM
Alfred, see post on Oct 17th.
19/Oct/15 8:38 AM
Loved NZ! Spent a month there in Nelson on south island with hubby while he worked there - did awesome trip around south island. Want to go back again for another visit.
19/Oct/15 3:41 PM
A9 :

f4=1 -> contradiction via [5i9=5a9-5a4=(5-3)h4=3i5]-(3=5)i9;
f4=3 -> contradiction via [(6=8)h2-8h4=8g4-8g78=HP(38)hi8]-6h8;
f4=5; UP81
19/Oct/15 9:06 PM
A-9,SE=9,0
SSTS
1)(8=6)h2-df2=(6-8)e1=(8)e3,=>gi3<>8
2)(38=6)ih8-(6=8)h2-h4=(8)g4,=>g 78<>8
3)(3)c8=hi8-(3=5)i9-(5=58)gac7,=>ac7<>3
4)(3)a954,=>h14<>8
(3)a9-(3 More...
25/Oct/15 1:09 AM
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