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Tough Sudoku

for 16/March/2006

                 
                 
                 
                 
                 
                 
                 
                 
                 

Choose a number, and place it in the grid above.

  1 2 3 4 5 6 7 8 9
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lana  From
Good maen all in sudokuland
Dan  From Oz
6.30
Hugh  From Glasgow
10:10
no1  From
16.24 where's the stairs?
ap india  From
oh my god!finished it in flat eight mts.yes me to wonder wheres the stairs going
Platypus  From Boston
OK, I got it, but I admit I was lucky. I was looking for a forcing chain and the whole thing broke on me.
Gaby  From Israel
Hi Dan from Oz,
You did it quite quick. Any system except setting up all possibilities and looking for figures with one option only?
Gaby
nic  From syd
Partial solution:
1. a3=b1=24 elim in box, easy to 27 filled
2. h1=h4=24 elim in col, easy to 54 filled
3. d8=e9=f9=469 elim in box
4. X wing on 9s d1,e1,d6,e6 => f9=9
nic  From syd
so, at 55 filled my grid looks like this:
5 7 3 1 4/6/9 4/6/9 2 8 4/5/6/9
1 8 2/4 4/6/9 2/7 5 4/7/9 3 4/6/7/9
9 6 2/4 8 3 2/7 4/5/7 1 4/5/7
4 2 5 6/9 6/9 3 1 7 8
7 9 8 4/5 1 2/4 3 6 2/5
6 3 1 7 2/5 8 5/9 4 2/5/9
2 5 6 3 8 4/7 4/7 9 1
3 1 9 2 4/6/7 4/6/7 8 5 4/7
8 4 7 5/9 5/9 1 6 2 3
nic  From syd
1 am, work tomorrow, so I'll dream of a forbidding chain :)
Burck  From Spongecake
A difficult one this...
I think I'll try it later...
naomi  From toronto canada
17.54 stuck at 27 filled...printing on paper and will try to finish. i'm still finding these really difficult to do...i can usually do 1 in 20 or 30...but then i used to find the 'hard' really difficult too, now they're always done
Cathy  From southern Ontario
No timer. Great moody picture! Take care, everyone.
Steve  From Ohio    Supporting Member
1) Start at 22 filled. Unique Possibilities to 27.
2) Hidden pair 69: d6=9 == e6=9 -- e6=6 == d6=6 forbids e4=9, d6=45, e6= 245.
Locked 5's forbid b4,c5=5. Locked 5's forbid b1=5.
3) The Almost Locked Set a6=247, b6=2457,c6=245,h6=247 and the wrap around chain:
b1=2 == b1=4 -- h1=4 == h1=2 forbid b4=42 ( note, b4=42 will either leave no 2's or no 4's in the ALS.)
4) UP to 56. X wing on 4's forbids e8, i78=4. i2=7 == e2=7 -- f3=7 == f7=7 forbids i7=7.
5) Up to 81
sets 14, depth 6
Judith  From Iowa
11:07 not bad for me
Great picture. I love the beach all year round.
andrei  From US
As a little provocation, let me offer this 'solution' using hints from Simple Sudoku (SS):
UP to 27; SS elims;
abc6=4==h6=4--h1=4==b1=4 elim b4=4; strong sets (i3=1,i2=1),(b2=1,b2=3),(h1=2,b1=2),(b4= 3,b4=2) elim i3=2; SS to end. Depth: 4! (Too many sets, I am sure; but they can be cleaned out with more time...).
Steve  From Ohio    Supporting Member
Note one can write the fc for eliminating 42 at b3 like this:
b1=2 == b1=4 -- h1=4 == h1=2
then note h6=4 == abc=4 and h6=2 == abc=2 to forbid d4=24.
Reduces depth to 3.
Steve  From Ohio    Supporting Member
Yes Andrei - cross posting there - depth 3 is possible - just I sort of like to eliminate them both with one fc... but two fc's of depth 3 suffice.
Steve  From Ohio    Supporting Member
I suppose if one uses pair 42 earlier, then depth 2 is possible.
Steve  From Ohio    Supporting Member
Same number of sets as my solution above, I think, just depth 2. Do the pair 42, then X wing style (from gb's nomenclature)on 4's and 2's to eliminate 42 at b4.
Steve  From Ohio    Supporting Member
Interestingly enough, perhaps, one can use the hidden pair 69, without doing any eliminations except locked 5's in row 1, to prove strong 4's and 2's in the hidden locked set 2457, which then with the pair 42 eliminate 24 at d4. My first proof above should have noted that I had a locked set, not an Almost Locked Set. Sorry about that.
Steve  From Ohio    Supporting Member
1) Start at 22 filled. Unique Possibilities to 27.
2) Hidden pair 69: d6=9 == e6=9 -- e6=6 == d6=6 forbids e4=9, d6=45, e6= 245.
Locked 5's forbid b4,c5=5. Locked 5's forbid b1=5.
3) Pair 42 at b1, h1. abc6=4==h6=4--h1=4==b1=4 elim b4=4;
abc6=2==h6=2--h1=2==b1=2 elim b4=2
4) UP to 56. X wing on 4's forbids e8, i78=4. i2=7 == e2=7 -- f3=7 == f7=7 forbids i7=7.
5) Up to 81
sets 14, depth 2
Steve  From Ohio    Supporting Member
I actually prefer my first proof, becuase of the symetry. But, latter proof is less deep.
Steve  From Ohio    Supporting Member
to nic: How did you eliminate 3 from h4?
Karen  From NR Oh
Woody  From Smithville, Canada
Forgot timer, but felt average (for me)
Nick  From Toronto
18:58 had one guess because I can't figure out Steve's comments.
Rob  From Liverpool
7:26
penguincity, Los Angeles  From CA USA
all 4 done for the day, so I guess I should finish lunch and get back to work
Hope everyone is enjoying the day.
Sue  From Australia
13:12
SUZ  From MD
16:20 w/ couple of guesses
Lorna  From Humobldt, Ca.
6:20
for Steve  From larryville in ks usa
re your first post on tough today, what do you mean by 'sets' and 'depth' in 'sets 14, depth 6'? Forgive my ignorance, please, and thanks so much for putting your thought processes out there for all to study.
for andrei  From larryville in ks usa
Thanks to you, too, for the same.
Steve  From Ohio    Supporting Member
By 'sets', we mean the number of 'strong' sets considered. 'Strong' sets being a set in which at least one of the possibilities listed must be true. By depth, we mean the number of strong sets considered at one time to produce an elimination. Generally, at the end of a proof, only the longest chain is mentioned. (maximum depth).
Steve  From Ohio    Supporting Member
Depth and sets are then some sort of objective measure of the difficulty of a proof.
Christina  From Newfoundland/France
Steve from Ohio - Considering the number of people who seem interested in learning....and given that terminology is always changing....it might be a good idea to consolidate some of this on a page somewhere - definitions, FAQ's. What do you think?
Yvette  From Rossendale, England    Supporting Member
4.12 no system just guesses!!!
To Steve from David  From Sydney
I am also a newbie and cant work out the jargon. What does abc6=2 mean?
tammy  From Sydney
14:51, lucky 'guess' looking for a forbidden chain...
I believe if you go to 'MORE' and 'PROOFS' that gb's nomenclature is explained there... this is the same I think as what Steve/Ohio uses. I admit to being a bit confused by it all, and just try to get through on my own anyway...
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